fftn(x, shape=None, axes=None, overwrite_x=False)¶
Return multidimensional discrete Fourier transform.
The returned array contains:
y[j_1,..,j_d] = sum[k_1=0..n_1-1, ..., k_d=0..n_d-1] x[k_1,..,k_d] * prod[i=1..d] exp(-sqrt(-1)*2*pi/n_i * j_i * k_i)
where d = len(x.shape) and n = x.shape. Note that
y[..., -j_i, ...] = y[..., n_i-j_i, ...].conjugate().
x : array_like
The (n-dimensional) array to transform.
shape : tuple of ints, optional
The shape of the result. If both shape and axes (see below) are None, shape is
x.shape; if shape is None but axes is not None, then shape is
scipy.take(x.shape, axes, axis=0). If
shape[i] > x.shape[i], the i-th dimension is padded with zeros. If
shape[i] < x.shape[i], the i-th dimension is truncated to length
axes : array_like of ints, optional
The axes of x (y if shape is not None) along which the transform is applied.
overwrite_x : bool, optional
If True, the contents of x can be destroyed. Default is False.
y : complex-valued n-dimensional numpy array
The (n-dimensional) DFT of the input array.
Both single and double precision routines are implemented. Half precision inputs will be converted to single precision. Non floating-point inputs will be converted to double precision. Long-double precision inputs are not supported.
>>> from scipy.fftpack import fftn, ifftn >>> y = (-np.arange(16), 8 - np.arange(16), np.arange(16)) >>> np.allclose(y, fftn(ifftn(y))) True