numpy.inner¶
- numpy.inner(a, b)¶
Inner product of two arrays.
Ordinary inner product of vectors for 1-D arrays (without complex conjugation), in higher dimensions a sum product over the last axes.
Parameters: a, b : array_like
If a and b are nonscalar, their last dimensions of must match.
Returns: out : ndarray
out.shape = a.shape[:-1] + b.shape[:-1]
Raises: ValueError :
If the last dimension of a and b has different size.
See also
Notes
For vectors (1-D arrays) it computes the ordinary inner-product:
np.inner(a, b) = sum(a[:]*b[:])
More generally, if ndim(a) = r > 0 and ndim(b) = s > 0:
np.inner(a, b) = np.tensordot(a, b, axes=(-1,-1))
or explicitly:
np.inner(a, b)[i0,...,ir-1,j0,...,js-1] = sum(a[i0,...,ir-1,:]*b[j0,...,js-1,:])
In addition a or b may be scalars, in which case:
np.inner(a,b) = a*b
Examples
Ordinary inner product for vectors:
>>> a = np.array([1,2,3]) >>> b = np.array([0,1,0]) >>> np.inner(a, b) 2
A multidimensional example:
>>> a = np.arange(24).reshape((2,3,4)) >>> b = np.arange(4) >>> np.inner(a, b) array([[ 14, 38, 62], [ 86, 110, 134]])
An example where b is a scalar:
>>> np.inner(np.eye(2), 7) array([[ 7., 0.], [ 0., 7.]])