numpy.setdiff1d¶
- numpy.setdiff1d(ar1, ar2, assume_unique=False)[source]¶
Find the set difference of two arrays.
Return the sorted, unique values in ar1 that are not in ar2.
Parameters : ar1 : array_like
Input array.
ar2 : array_like
Input comparison array.
assume_unique : bool
If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
Returns : setdiff1d : ndarray
Sorted 1D array of values in ar1 that are not in ar2.
See also
- numpy.lib.arraysetops
- Module with a number of other functions for performing set operations on arrays.
Examples
>>> a = np.array([1, 2, 3, 2, 4, 1]) >>> b = np.array([3, 4, 5, 6]) >>> np.setdiff1d(a, b) array([1, 2])