numpy.ma.resize¶
- numpy.ma.resize(x, new_shape)[source]¶
Return a new masked array with the specified size and shape.
This is the masked equivalent of the numpy.resize function. The new array is filled with repeated copies of x (in the order that the data are stored in memory). If x is masked, the new array will be masked, and the new mask will be a repetition of the old one.
See also
- numpy.resize
- Equivalent function in the top level NumPy module.
Examples
>>> import numpy.ma as ma >>> a = ma.array([[1, 2] ,[3, 4]]) >>> a[0, 1] = ma.masked >>> a masked_array(data = [[1 --] [3 4]], mask = [[False True] [False False]], fill_value = 999999) >>> np.resize(a, (3, 3)) array([[1, 2, 3], [4, 1, 2], [3, 4, 1]]) >>> ma.resize(a, (3, 3)) masked_array(data = [[1 -- 3] [4 1 --] [3 4 1]], mask = [[False True False] [False False True] [False False False]], fill_value = 999999)
A MaskedArray is always returned, regardless of the input type.
>>> a = np.array([[1, 2] ,[3, 4]]) >>> ma.resize(a, (3, 3)) masked_array(data = [[1 2 3] [4 1 2] [3 4 1]], mask = False, fill_value = 999999)