Wrapped Cauchy DistributionΒΆ
There is one shape parameter \(c\in\left(0,1\right)\) with support \(x\in\left[0,2\pi\right]\).
\begin{eqnarray*} f\left(x;c\right) & = & \frac{1-c^{2}}{2\pi\left(1+c^{2}-2c\cos x\right)}\\
g_{c}\left(x\right) & = & \frac{1}{\pi}\arctan\left(\frac{1+c}{1-c}\tan\left(\frac{x}{2}\right)\right)\\
r_{c}\left(q\right) & = & 2\arctan\left(\frac{1-c}{1+c}\tan\left(\pi q\right)\right)\\
F\left(x;c\right) & = & \left\{
\begin{array}{ccc}
g_{c}\left(x\right) & & 0\leq x<\pi\\
1-g_{c}\left(2\pi-x\right) & & \pi\leq x\leq2\pi
\end{array}
\right.\\
G\left(q;c\right) & = & \left\{
\begin{array}{ccc}
r_{c}\left(q\right) & & 0\leq q<\frac{1}{2}\\
2\pi-r_{c}\left(1-q\right) & & \frac{1}{2}\leq q\leq1
\end{array}
\right.\end{eqnarray*}
\[h\left[X\right]=\log\left(2\pi\left(1-c^{2}\right)\right).\]
Implementation: scipy.stats.wrapcauchy