SciPy

scipy.integrate.DenseOutput.__call__

DenseOutput.__call__(t)[source]

Evaluate the interpolant.

Parameters:

t : float or array_like with shape (n_points,)

Points to evaluate the solution at.

Returns:

y : ndarray, shape (n,) or (n, n_points)

Computed values. Shape depends on whether t was a scalar or a 1-d array.