scipy.spatial.distance.squareform(X, force='no', checks=True)[source]

Converts a vector-form distance vector to a square-form distance matrix, and vice-versa.


X : ndarray

Either a condensed or redundant distance matrix.

force : str, optional

As with MATLAB(TM), if force is equal to ‘tovector’ or ‘tomatrix’, the input will be treated as a distance matrix or distance vector respectively.

checks : bool, optional

If checks is set to False, no checks will be made for matrix symmetry nor zero diagonals. This is useful if it is known that X - X.T1 is small and diag(X) is close to zero. These values are ignored any way so they do not disrupt the squareform transformation.


Y : ndarray

If a condensed distance matrix is passed, a redundant one is returned, or if a redundant one is passed, a condensed distance matrix is returned.


  1. v = squareform(X)

    Given a square d-by-d symmetric distance matrix X, v=squareform(X) returns a d * (d-1) / 2 (or ${n choose 2}$) sized vector v.

v[{n choose 2}-{n-i choose 2} + (j-i-1)] is the distance between points i and j. If X is non-square or asymmetric, an error is returned.
  1. X = squareform(v)
Given a d*d(-1)/2 sized v for some integer d>=2 encoding distances as described, X=squareform(v) returns a d by d distance matrix X. The X[i, j] and X[j, i] values are set to v[{n choose 2}-{n-i choose 2} + (j-u-1)] and all diagonal elements are zero.