scipy.signal.residuez¶
- scipy.signal.residuez(b, a, tol=0.001, rtype='avg')[source]¶
Compute partial-fraction expansion of b(z) / a(z).
If M = len(b) and N = len(a):
b(z) b[0] + b[1] z**(-1) + ... + b[M-1] z**(-M+1) H(z) = ------ = ---------------------------------------------- a(z) a[0] + a[1] z**(-1) + ... + a[N-1] z**(-N+1) r[0] r[-1] = --------------- + ... + ---------------- + k[0] + k[1]z**(-1) ... (1-p[0]z**(-1)) (1-p[-1]z**(-1))
If there are any repeated roots (closer than tol), then the partial fraction expansion has terms like:
r[i] r[i+1] r[i+n-1] -------------- + ------------------ + ... + ------------------ (1-p[i]z**(-1)) (1-p[i]z**(-1))**2 (1-p[i]z**(-1))**n
See also