scipy.stats.mstats.count_tied_groups¶
- scipy.stats.mstats.count_tied_groups(x, use_missing=False)[source]¶
Counts the number of tied values.
Parameters : x : sequence
Sequence of data on which to counts the ties
use_missing : boolean
Whether to consider missing values as tied.
Returns : count_tied_groups : dict
Returns a dictionary (nb of ties: nb of groups).
Examples
>>> z = [0, 0, 0, 2, 2, 2, 3, 3, 4, 5, 6] >>> count_tied_groups(z) >>> {2:1, 3:2} >>> # The ties were 0 (3x), 2 (3x) and 3 (2x) >>> z = ma.array([0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6]) >>> count_tied_groups(z) >>> {2:2, 3:1} >>> # The ties were 0 (2x), 2 (3x) and 3 (2x) >>> z[[1,-1]] = masked >>> count_tied_groups(z, use_missing=True) >>> {2:2, 3:1} >>> # The ties were 2 (3x), 3 (2x) and masked (2x)