scipy.spatial can compute triangulations, Voronoi diagrams, and convex hulls of a set of points, by leveraging the Qhull library.
Moreover, it contains KDTree implementations for nearest-neighbor point queries, and utilities for distance computations in various metrics.
The Delaunay triangulation is a subdivision of a set of points into a non-overlapping set of triangles, such that no point is inside the circumcircle of any triangle. In practice, such triangulations tend to avoid triangles with small angles.
Delaunay triangulation can be computed using scipy.spatial as follows:
>>> from scipy.spatial import Delaunay
>>> points = np.array([[0, 0], [0, 1.1], [1, 0], [1, 1]])
>>> tri = Delaunay(points)
We can visualize it:
>>> import matplotlib.pyplot as plt
>>> plt.triplot(points[:,0], points[:,1], tri.simplices.copy())
>>> plt.plot(points[:,0], points[:,1], 'o')
And add some further decorations:
>>> for j, p in enumerate(points):
... plt.text(p[0]-0.03, p[1]+0.03, j, ha='right') # label the points
>>> for j, s in enumerate(tri.simplices):
... p = points[s].mean(axis=0)
... plt.text(p[0], p[1], '#%d' % j, ha='center') # label triangles
>>> plt.xlim(-0.5, 1.5); plt.ylim(-0.5, 1.5)
>>> plt.show()
The structure of the triangulation is encoded in the following way: the simplices attribute contains the indices of the points in the points array that make up the triangle. For instance:
>>> i = 1
>>> tri.simplices[i,:]
array([3, 1, 0], dtype=int32)
>>> points[tri.simplices[i,:]]
array([[ 1. , 1. ],
[ 0. , 1.1],
[ 0. , 0. ]])
Moreover, neighboring triangles can also be found out:
>>> tri.neighbors[i]
array([-1, 0, -1], dtype=int32)
What this tells us is that this triangle has triangle #0 as a neighbor, but no other neighbors. Moreover, it tells us that neighbor 0 is opposite the vertex 1 of the triangle:
>>> points[tri.simplices[i, 1]]
array([ 0. , 1.1])
Indeed, from the figure we see that this is the case.
Qhull can also perform tesselations to simplices also for higher-dimensional point sets (for instance, subdivision into tetrahedra in 3-D).
It is important to note that not all points necessarily appear as vertices of the triangulation, due to numerical precision issues in forming the triangulation. Consider the above with a duplicated point:
>>> points = np.array([[0, 0], [0, 1], [1, 0], [1, 1], [1, 1]])
>>> tri = Delaunay(points)
>>> np.unique(tri.simplices.ravel())
array([0, 1, 2, 3], dtype=int32)
Observe that point #4, which is a duplicate, does not occur as a vertex of the triangulation. That this happened is recorded:
>>> tri.coplanar
array([[4, 0, 3]], dtype=int32)
This means that point 4 resides near triangle 0 and vertex 3, but is not included in the triangulation.
Note that such degeneracies can occur not only because of duplicated points, but also for more complicated geometrical reasons, even in point sets that at first sight seem well-behaved.
However, Qhull has the “QJ” option, which instructs it to perturb the input data randomly until degeneracies are resolved:
>>> tri = Delaunay(points, qhull_options="QJ Pp")
>>> points[tri.simplices]
array([[[1, 1],
[1, 0],
[0, 0]],
[[1, 1],
[1, 1],
[1, 0]],
[[0, 1],
[1, 1],
[0, 0]],
[[0, 1],
[1, 1],
[1, 1]]])
Two new triangles appeared. However, we see that they are degenerate and have zero area.
Convex hull is the smallest convex object containing all points in a given point set.
These can be computed via the Qhull wrappers in scipy.spatial as follows:
>>> from scipy.spatial import ConvexHull
>>> points = np.random.rand(30, 2) # 30 random points in 2-D
>>> hull = ConvexHull(points)
The convex hull is represented as a set of N-1 dimensional simplices, which in 2-D means line segments. The storage scheme is exactly the same as for the simplices in the Delaunay triangulation discussed above.
We can illustrate the above result:
>>> import matplotlib.pyplot as plt
>>> plt.plot(points[:,0], points[:,1], 'o')
>>> for simplex in hull.simplices:
>>> plt.plot(points[simplex,0], points[simplex,1], 'k-')
>>> plt.show()
The same can be achieved with scipy.spatial.convex_hull_plot_2d.
A Voronoi diagram is a subdivision of the space into the nearest neighborhoods of a given set of points.
There are two ways to approach this object using scipy.spatial. First, one can use the KDTree to answer the question “which of the points is closest to this one”, and define the regions that way:
>>> from scipy.spatial import KDTree
>>> points = np.array([[0, 0], [0, 1], [0, 2], [1, 0], [1, 1], [1, 2],
... [2, 0], [2, 1], [2, 2]])
>>> tree = KDTree(points)
>>> tree.query([0.1, 0.1])
(0.14142135623730953, 0)
So the point (0.1, 0.1) belongs to region 0. In color:
>>> x = np.linspace(-0.5, 2.5, 31)
>>> y = np.linspace(-0.5, 2.5, 33)
>>> xx, yy = np.meshgrid(x, y)
>>> xy = np.c_[xx.ravel(), yy.ravel()]
>>> import matplotlib.pyplot as plt
>>> plt.pcolor(x, y, tree.query(xy)[1].reshape(33, 31))
>>> plt.plot(points[:,0], points[:,1], 'ko')
>>> plt.show()
This does not, however, give the Voronoi diagram as a geometrical object.
The representation in terms of lines and points can be again obtained via the Qhull wrappers in scipy.spatial:
>>> from scipy.spatial import Voronoi
>>> vor = Voronoi(points)
>>> vor.vertices
array([[ 0.5, 0.5],
[ 1.5, 0.5],
[ 0.5, 1.5],
[ 1.5, 1.5]])
The Voronoi vertices denote the set of points forming the polygonal edges of the Voronoi regions. In this case, there are 9 different regions:
>>> vor.regions
[[-1, 0], [-1, 1], [1, -1, 0], [3, -1, 2], [-1, 3], [-1, 2], [3, 1, 0, 2], [2, -1, 0], [3, -1, 1]]
Negative value -1 again indicates a point at infinity. Indeed, only one of the regions, [3, 1, 0, 2], is bounded. Note here that due to similar numerical precision issues as in Delaunay triangulation above, there may be fewer Voronoi regions than input points.
The ridges (lines in 2-D) separating the regions are described as a similar collection of simplices as the convex hull pieces:
>>> vor.ridge_vertices
[[-1, 0], [-1, 0], [-1, 1], [-1, 1], [0, 1], [-1, 3], [-1, 2], [2, 3], [-1, 3], [-1, 2], [0, 2], [1, 3]]
These numbers indicate indices of the Voronoi vertices making up the line segments. -1 is again a point at infinity — only four of the 12 lines is a bounded line segment while the others extend to infinity.
The Voronoi ridges are perpendicular to lines drawn between the input points. Which two points each ridge corresponds to is also recorded:
>>> vor.ridge_points
array([[0, 3],
[0, 1],
[6, 3],
[6, 7],
[3, 4],
[5, 8],
[5, 2],
[5, 4],
[8, 7],
[2, 1],
[4, 1],
[4, 7]], dtype=int32)
This information, taken together, is enough to construct the full diagram.
We can plot it as follows. First the points and the Voronoi vertices:
>>> plt.plot(points[:,0], points[:,1], 'o')
>>> plt.plot(vor.vertices[:,0], vor.vertices[:,1], '*')
>>> plt.xlim(-1, 3); plt.ylim(-1, 3)
Plotting the finite line segments goes as for the convex hull, but now we have to guard for the infinite edges:
>>> for simplex in vor.ridge_vertices:
>>> simplex = np.asarray(simplex)
>>> if np.all(simplex >= 0):
>>> plt.plot(vor.vertices[simplex,0], vor.vertices[simplex,1], 'k-')
The ridges extending to infinity require a bit more care:
>>> center = points.mean(axis=0)
>>> for pointidx, simplex in zip(vor.ridge_points, vor.ridge_vertices):
>>> simplex = np.asarray(simplex)
>>> if np.any(simplex < 0):
>>> i = simplex[simplex >= 0][0] # finite end Voronoi vertex
>>> t = points[pointidx[1]] - points[pointidx[0]] # tangent
>>> t /= np.linalg.norm(t)
>>> n = np.array([-t[1], t[0]]) # normal
>>> midpoint = points[pointidx].mean(axis=0)
>>> far_point = vor.vertices[i] + np.sign(np.dot(midpoint - center, n)) * n * 100
>>> plt.plot([vor.vertices[i,0], far_point[0]],
... [vor.vertices[i,1], far_point[1]], 'k--')
>>> plt.show()
This plot can also be created using scipy.spatial.voronoi_plot_2d.