Compute the truth value of x1 XOR x2, element-wise.
| Parameters : | x1, x2 : array_like 
  | 
|---|---|
| Returns : | y : bool or ndarray of bool 
  | 
See also
Examples
>>> np.logical_xor(True, False)
True
>>> np.logical_xor([True, True, False, False], [True, False, True, False])
array([False,  True,  True, False], dtype=bool)
>>> x = np.arange(5)
>>> np.logical_xor(x < 1, x > 3)
array([ True, False, False, False,  True], dtype=bool)
Simple example showing support of broadcasting
>>> np.logical_xor(0, np.eye(2))
array([[ True, False],
       [False,  True]], dtype=bool)