Compute the truth value of x1 XOR x2, element-wise.
Parameters : | x1, x2 : array_like
|
---|---|
Returns : | y : bool or ndarray of bool
|
See also
Examples
>>> np.logical_xor(True, False)
True
>>> np.logical_xor([True, True, False, False], [True, False, True, False])
array([False, True, True, False], dtype=bool)
>>> x = np.arange(5)
>>> np.logical_xor(x < 1, x > 3)
array([ True, False, False, False, True], dtype=bool)
Simple example showing support of broadcasting
>>> np.logical_xor(0, np.eye(2))
array([[ True, False],
[False, True]], dtype=bool)