numpy.right_shift¶

numpy.
right_shift
(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'right_shift'>¶ Shift the bits of an integer to the right.
Bits are shifted to the right x2. Because the internal representation of numbers is in binary format, this operation is equivalent to dividing x1 by
2**x2
.Parameters:  x1 : array_like, int
Input values.
 x2 : array_like, int
Number of bits to remove at the right of x1. If
x1.shape != x2.shape
, they must be broadcastable to a common shape (which becomes the shape of the output). out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshlyallocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
 where : array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the out array will be set to the ufunc result. Elsewhere, the out array will retain its original value. Note that if an uninitialized out array is created via the default
out=None
, locations within it where the condition is False will remain uninitialized. **kwargs
For other keywordonly arguments, see the ufunc docs.
Returns:  out : ndarray, int
Return x1 with bits shifted x2 times to the right. This is a scalar if both x1 and x2 are scalars.
See also
left_shift
 Shift the bits of an integer to the left.
binary_repr
 Return the binary representation of the input number as a string.
Examples
>>> np.binary_repr(10) '1010' >>> np.right_shift(10, 1) 5 >>> np.binary_repr(5) '101'
>>> np.right_shift(10, [1,2,3]) array([5, 2, 1])