numpy.floor_divide¶

numpy.
floor_divide
(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'floor_divide'>¶ Return the largest integer smaller or equal to the division of the inputs. It is equivalent to the Python
//
operator and pairs with the Python%
(remainder
), function so thata = a % b + b * (a // b)
up to roundoff.Parameters:  x1 : array_like
Numerator.
 x2 : array_like
Denominator. If
x1.shape != x2.shape
, they must be broadcastable to a common shape (which becomes the shape of the output). out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshlyallocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
 where : array_like, optional
This condition is broadcast over the input. At locations where the condition is True, the out array will be set to the ufunc result. Elsewhere, the out array will retain its original value. Note that if an uninitialized out array is created via the default
out=None
, locations within it where the condition is False will remain uninitialized. **kwargs
For other keywordonly arguments, see the ufunc docs.
Returns:  y : ndarray
y = floor(x1/x2) This is a scalar if both x1 and x2 are scalars.
See also
Examples
>>> np.floor_divide(7,3) 2 >>> np.floor_divide([1., 2., 3., 4.], 2.5) array([ 0., 0., 1., 1.])