numpy.spacing¶

numpy.
spacing
(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'spacing'>¶ Return the distance between x and the nearest adjacent number.
Parameters:  x : array_like
Values to find the spacing of.
 out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshlyallocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
 where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
 **kwargs
For other keywordonly arguments, see the ufunc docs.
Returns:  out : ndarray or scalar
The spacing of values of x. This is a scalar if x is a scalar.
Notes
It can be considered as a generalization of EPS:
spacing(np.float64(1)) == np.finfo(np.float64).eps
, and there should not be any representable number betweenx + spacing(x)
and x for any finite x.Spacing of + inf and NaN is NaN.
Examples
>>> np.spacing(1) == np.finfo(np.float64).eps True