numpy.floor_divide¶

numpy.
floor_divide
(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'floor_divide'>¶ Return the largest integer smaller or equal to the division of the inputs. It is equivalent to the Python
//
operator and pairs with the Python%
(remainder
), function so thatb = a % b + b * (a // b)
up to roundoff.Parameters:  x1 : array_like
Numerator.
 x2 : array_like
Denominator.
 out : ndarray, None, or tuple of ndarray and None, optional
A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshlyallocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.
 where : array_like, optional
Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.
 **kwargs
For other keywordonly arguments, see the ufunc docs.
Returns:  y : ndarray
y = floor(x1/x2) This is a scalar if both x1 and x2 are scalars.
See also
Examples
>>> np.floor_divide(7,3) 2 >>> np.floor_divide([1., 2., 3., 4.], 2.5) array([ 0., 0., 1., 1.])