numpy.linalg.pinv¶

numpy.linalg.pinv(a, rcond=1e-15)[source]¶

Compute the (Moore-Penrose) pseudo-inverse of a matrix.

Calculate the generalized inverse of a matrix using its singular-value decomposition (SVD) and including all large singular values.

Changed in version 1.14: Can now operate on stacks of matrices

Parameters:

Parameters:	a : (…, M, N) array_like Matrix or stack of matrices to be pseudo-inverted. rcond : (…) array_like of float Cutoff for small singular values. Singular values smaller (in modulus) than rcond * largest_singular_value (again, in modulus) are set to zero. Broadcasts against the stack of matrices
Returns:	B : (…, N, M) ndarray The pseudo-inverse of a. If a is a matrix instance, then so is B.
Raises:	LinAlgError If the SVD computation does not converge.

a : (…, M, N) array_like

Matrix or stack of matrices to be pseudo-inverted.

rcond : (…) array_like of float

Cutoff for small singular values. Singular values smaller (in modulus) than rcond * largest_singular_value (again, in modulus) are set to zero. Broadcasts against the stack of matrices

Returns:

B : (…, N, M) ndarray

The pseudo-inverse of a. If a is a matrix instance, then so is B.

Raises:

LinAlgError

If the SVD computation does not converge.

Notes

The pseudo-inverse of a matrix A, denoted $A^+$ , is defined as: “the matrix that ‘solves’ [the least-squares problem] $Ax = b$ ,” i.e., if $\bar{x}$ is said solution, then $A^+$ is that matrix such that $\bar{x} = A^+b$ .

It can be shown that if $Q_1 \Sigma Q_2^T = A$ is the singular value decomposition of A, then $A^+ = Q_2 \Sigma^+ Q_1^T$ , where $Q_{1,2}$ are orthogonal matrices, $\Sigma$ is a diagonal matrix consisting of A’s so-called singular values, (followed, typically, by zeros), and then $\Sigma^+$ is simply the diagonal matrix consisting of the reciprocals of A’s singular values (again, followed by zeros). [R8787]

References

[R8787]

(1, 2) G. Strang, Linear Algebra and Its Applications, 2nd Ed., Orlando, FL, Academic Press, Inc., 1980, pp. 139-142.

Examples

The following example checks that a * a+ * a == a and a+ * a * a+ == a+:

>>> a = np.random.randn(9, 6)
>>> B = np.linalg.pinv(a)
>>> np.allclose(a, np.dot(a, np.dot(B, a)))
True
>>> np.allclose(B, np.dot(B, np.dot(a, B)))
True

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