
DYNAMICS  CASE STUDY



Introduction

Train Motion


A highspeed train is traveling at 50 m/s when the first half of the train, which includes the engine, breaks away from the second half. Due to the loss in weight and drag, the first half of the train accelerates for two seconds before the engineer regains control.
What is known:
 The train is moving along a linear path.
 The train had been traveling at 50 m/s for 2 seconds when the break occurs.
 The acceleration of the first half of the train after the break at t = 2 sec is
a(t) = 2t m/s^{2} 2 ≤ t ≤ 4 seconds




Train conditions over time


Question


Knowing the acceleration of the train as a function of time after the break, what is the velocity of the first half of the train at t = 4 seconds, and how far does it travel from t = 2 to t = 4 seconds?




Approach


 Begin begin with an equation for the acceleration and integrate, rather than begin with an equation for the position and differentiate as was done in the Position, Velocity, Acceleration section.
 Integrate
the basic acceleration equation (a = d^{2}x/dt^{2})
to find expressions for the velocity and position of the train.




