numpy.ma.choose¶
- numpy.ma.choose(indices, choices, out=None, mode='raise')[source]¶
Use an index array to construct a new array from a set of choices.
Given an array of integers and a set of n choice arrays, this method will create a new array that merges each of the choice arrays. Where a value in a is i, the new array will have the value that choices[i] contains in the same place.
Parameters: a : ndarray of ints
This array must contain integers in [0, n-1], where n is the number of choices.
choices : sequence of arrays
Choice arrays. The index array and all of the choices should be broadcastable to the same shape.
out : array, optional
If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype.
mode : {‘raise’, ‘wrap’, ‘clip’}, optional
Specifies how out-of-bounds indices will behave.
- ‘raise’ : raise an error
- ‘wrap’ : wrap around
- ‘clip’ : clip to the range
Returns: merged_array : array
See also
- choose
- equivalent function
Examples
>>> choice = np.array([[1,1,1], [2,2,2], [3,3,3]]) >>> a = np.array([2, 1, 0]) >>> np.ma.choose(a, choice) masked_array(data = [3 2 1], mask = False, fill_value=999999)